
And then there's the cast on. Using the long tail method, I pulled a length of wool from the ball, started with my slip knot and then added stitches. On my first attempt, the tail wasn't nearly long enough - I ran out at 72 stitches. On my second try I got as far as 180 stitches , but still not enough tail. Third time was the charm. Although I was so frustrated that I erred on the side of caution and was left with a couple yards extra on the tail with 224 stitches on the needle.
This happens to me more often than not and it's got me thinking ... I should be able to predict how much yarn is needed for the tail. Today I'm going to work on a formula ... [(number of stitches) x (diameter of needle x π) x (1.10 or some sort of ease factor)]+ (extra tail for weaving in). Really, isn't this what all my math studies were leading up to?
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